✅ – venus – 12-02 Oct 9
Looking for possible regex solution, since I still suck at it. The goal of the regex is to validate if string fits the format.
First should be random length string, then comes colon (
:
) and the last is one of two options: desc
or asc
.
someString:desc|asc
Examples: firstName:desc
, lastName:asc
7 Replies
@venus have you tried with
/\w+:(desc|asc)/
?You can play with it on https://regex101.com/r/EcV8bn/1
regex101
regex101: build, test, and debug regex
Regular expression tester with syntax highlighting, explanation, cheat sheet for PHP/PCRE, Python, GO, JavaScript, Java, C#/.NET.
Looks good to me, thanks. But when I add some string after
desc
or asc
it will still return true value:
You can make regex to check for end of string after
desc|asc
via $
Beautiful! Thank you
This question has an answer! Thank you for helping 😄
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