_mercury 🇵🇸•3y ago

_mercury – 19-03 Jul 23

I have an array of objects like above ... suppose it has many objs So how to get the object with abbreviation en-US ? from the array by array accessing ? labels['en-US]` seems not to work .. it should be one line because i use it in EJS view engine

16 Replies

ScriptyChris•3y ago

Like this?

.filter(({ abbreviation }) => abbreviation === 'en-US')

.filter(({ abbreviation }) => abbreviation === 'en-US')

_mercury 🇵🇸OP•3y ago

mmm Ok thx , i think i should remap the array of objs

Unknown User•3y ago

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_mercury 🇵🇸OP•3y ago

yes

_mercury 🇵🇸OP•3y ago

so how i convert this to an array to get the label by locals[abbreviation]

_mercury 🇵🇸OP•3y ago

to be easy to access @ScriptyChris

ScriptyChris•3y ago

Use .find() instead of .filter() so it will give you first object, which has 'en-US' as abbreviation and then you can use object.abbreviation

_mercury 🇵🇸OP•3y ago

I am thinking of restructure the obove obj

ScriptyChris•3y ago

What do you mean?

_mercury 🇵🇸OP•3y ago

    const attr_lbs_remapped = [];
    attr_labels.map((label) => {
      return (attr_lbs_remapped[label.abbreviation] = label.label);
    });

    const attr_lbs_remapped = [];
    attr_labels.map((label) => {
      return (attr_lbs_remapped[label.abbreviation] = label.label);
    });

This does not work You may understand what i mean from the code Instead of array of objs It should be easy to be associative array ? Key : abbreviation, value : label

ScriptyChris•3y ago

I don't have idea what are you trying to do 🤔 What structure do you want to have as an output?

_mercury 🇵🇸OP•3y ago

thx for your active help I did it

    const remapped_labels = {};
    attr_labels.forEach((label) => {
      remapped_labels[label.abbreviation] = label.label;
    });

    const remapped_labels = {};
    attr_labels.forEach((label) => {
      remapped_labels[label.abbreviation] = label.label;
    });

if there is a better way , thx to tell

ScriptyChris•3y ago

This should work

const remapped_labels = Object.fromEntries(
  attr_labels.map(({ abbreviation, label }) => [abbreviation, label])
)

const remapped_labels = Object.fromEntries(
  attr_labels.map(({ abbreviation, label }) => [abbreviation, label])
)

_mercury 🇵🇸OP•3y ago

Very good .. works

ScriptyChris•3y ago

Okay

reactibot•3y ago

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_mercury – 19-03 Jul 23

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